From 93f823694119584a1a5adffafc92230f4181483b Mon Sep 17 00:00:00 2001
From: =?utf8?q?Michal=20Mal=C3=BD?= <madcatxster@devoid-pointer.net>
Date: Fri, 16 Oct 2015 16:55:32 +0200
Subject: [PATCH] =?utf8?q?Opravit=20=C5=A1patn=C4=9B=20zapsan=C3=A9=20?=
 =?utf8?q?=C4=8D=C3=ADseln=C3=A9=20hodnoty=20a=20pou=C5=BE=C3=ADt=20cNaA?=
 =?utf8?q?=20m=C3=ADsto=20cHA=20ve=20v=C3=BDpo=C4=8Dtu=20pH=20fosfore?=
 =?utf8?q?=C4=8Dnanu=20draseln=C3=A9ho?=
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---
 tzach_problems_solved.tex | 4 ++--
 1 file changed, 2 insertions(+), 2 deletions(-)

diff --git a/tzach_problems_solved.tex b/tzach_problems_solved.tex
index e5e73f6..025123b 100644
--- a/tzach_problems_solved.tex
+++ b/tzach_problems_solved.tex
@@ -650,7 +650,7 @@
 
   \FloatJail{calculation}{Výpočet pH fosforečnanu draselného}{
    \begin{align*}
-    pH &= -\log \sqrt{\frac{K_W K_A}{c_{HA}}} \\
+    pH &= -\log \sqrt{\frac{K_W K_A}{c_{NaA}}} \\
     pH &= -\log \sqrt{\frac{10^{-14} \cdot 10^{\num{12,32}}}{10^{-3}}} \\
     pH &= \num{11,66}
    \end{align*}
@@ -665,7 +665,7 @@
 
   \FloatJail{calculation}{Vliv úbytku disociací}{
    \rmm{
-    \frac{[OH^-]}{c_{HA}} = \frac{10^{-5,625}}{10^{-2}} = \num{0,021}
+    \frac{[OH^-]}{c_{NaA}} = \frac{10^{-5,625}}{10^{-3}} = \num{0,002}
     }
    \infloattext{\centering Nelze zanedbat, protože řešení kvadratických rovnic není nikdy dost otravné \large{\Stopsign}}
   }
-- 
2.43.5