Pár drobných oprav všude možně

diff --git a/tzach_problems_solved.tex b/tzach_problems_solved.tex
index 2cd7fedb55923e8c2852c220f073fd2564c367c3..f542f999cbe668151a1a9491752d5c895988a057 100644 (file)
--- a/tzach_problems_solved.tex
+++ b/tzach_problems_solved.tex
@@ -1279,7 +1279,7 @@
   \paragraph{Zadání}
   Určete směr oxidačně-redukční reakce \ilm{2\:Fe^{3+} + 2\:I^- \rightleftharpoons 2\:Fe^{2+} + I_2} \\
   \begin{tabular}{l>{=}cr}
-   \ilm{E^\stdpot(I_2/2I^-)} && \num{+0,57}~\si{\volt} \\
+   \ilm{E^\stdpot(I_2/2I^-)} && \num{+0,54}~\si{\volt} \\
    \ilm{E^\stdpot(Fe^{3+}/Fe^{2+})} && \num{+0,77}~\si{\volt}
   \end{tabular}
 
@@ -1932,7 +1932,7 @@
     [OH^-]     &= \sqrt{K_B c_{HA}} \\
     [OH^-]     &= \sqrt{\num{2,042e-10} \cdot \num{1,5e-5}} \\
     [OH^-]     &= \sqrt{\num{3,063e-15}} \\
-    [OH^-]     &= \num{5,534e-8}\:[\si{\mpdm}] \\
+    [OH^-]     &= \SI{5,534e-8}{\mpdm} \\
     pOH                &= -\log\left(\num{5,534e-8}\right) = \num{7,256} \\
     pH         &= 14 - \num{7,256} \\
     pH         &= \num{6,743}
@@ -1956,9 +1956,9 @@
     [OH^-] &= \sqrt{K_b c_{HA} + K_W} \\
     [OH^-] &= \sqrt{\num{2,042e-10} \cdot \num{1,5e-5} + \num{1e-14}} \\
     [OH^-] &= \sqrt{\num{1,306e-14}} \\
-    [OH^-] &= \num{1,143}\:[\si{\mpdm}] \\
+    [OH^-] &= \SI{1,143e-7}{\mpdm} \\
     pOH    &= \num{6,942} \\
-    pH    &= \num{7,085}
+    pH    &= \num{7,058}
    \end{align*}
   }
 
@@ -2006,7 +2006,7 @@
   \FloatJail{calculation}{Potenciál v ekvivalenci}{
    \begin{align*}
     E_{ekv}    &= \frac{n_1 E_1 + n_2 E_2}{n_1 + n_2} \\
-    E_{ekv}    &= \frac{6 \cdot \num{1,360} + 2 \cdot \num{0,139}}{1 + 3} \\
+    E_{ekv}    &= \frac{6 \cdot \num{1,360} + 2 \cdot \num{0,139}}{2 + 6} \\
     E_{ekv}    &= \frac{\num{8,438}}{8} \\
     E_{ekv}    &= \SI{1,055}{\volt}
    \end{align*}